Assembly language program to count the number of 1’s and 0’s in the binary bit system

Step 1 : Load register A (accumulator) with the given data

Step 2 : Load register B with 08H to set up a decrement counter

Step 3 : Load register C as counter to count the numbers of 1’s (initial value 00H)

Step 4 : Load register D as counter to count the number of 0’s (initial value 00H)

Step 5 : Rotate the content of Accumulator to left through carry

Step 6 : If on carry from Step 5 then jump directly to Step 9

Step 7 : Else increase counter C by 1

Step 8 : Jump unconditionally to Step 10

Step 9 : Increase counter D by 1

Step 10 : Decrease counter B by 1

Step 11 : Until B is not equal to 0 repeat from Step 5

Label	Instructions	Comments
	MVI A, CDH;	Loads register A (accumulator) with data stream
	MVI B, 08H;	Sets up decrement counter
	MVI C, 00H;	Sets counter to count number of 1’s
	MVI D, 00H;	Sets counter to count number of 0’s
jump2:	RAL;	Rotate accumulator left through carry
	JNC jump1:;	On no carry jumps to jump1:
	INR C;	Increases counter C by one
	JMP jump3:;	Jumps unconditionally to jump3:
jump1:	INR D;	Increases counter D by one
jump3:	DCR B;	Decreases counter B by one
	JNZ jump2:;	On B not equal to 0 jumps to jump2:
	HLT;	Terminates the program